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December 20, 2014

December 20, 2014

Posted by **jason** on Friday, November 16, 2012 at 10:38pm.

spring 5.63 cm from its unstressed length.

How much the extra work is required to

stretch it an additional 4.22 cm?

Answer in units of J

- science -
**drwls**, Saturday, November 17, 2012 at 8:08amTo stretch 4.22+5.63 = 9.85 cm, that is

(9.85/5.63) = 1.750 times the initial stretch amount. The energy required is the square of that ratio (3.06 times) higher than before.

Energy required went from 3.38 J to 10.35 J

The extra work is the difference of thse numbers.

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