Saturday

January 31, 2015

January 31, 2015

Posted by **jason** on Friday, November 16, 2012 at 10:38pm.

spring 5.63 cm from its unstressed length.

How much the extra work is required to

stretch it an additional 4.22 cm?

Answer in units of J

- science -
**drwls**, Saturday, November 17, 2012 at 8:08amTo stretch 4.22+5.63 = 9.85 cm, that is

(9.85/5.63) = 1.750 times the initial stretch amount. The energy required is the square of that ratio (3.06 times) higher than before.

Energy required went from 3.38 J to 10.35 J

The extra work is the difference of thse numbers.

**Answer this Question**

**Related Questions**

Physics (2) - If it takes 4.00 J of work to stretch a Hooke's Law spring 10.0 cm...

PHYSICS - If it takes 4.12 J of work to stretch a Hooke's law spring 12.1 cm ...

physics - It takes 5.28 J of work to stretch a Hookes Laq spring 9.82 cm from ...

physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...

Physics - Hooke's law states that it takes a force equal to kΔx is required...

physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...

Physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...

Physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...

physics - If it requires 5.5 J of work to stretch a particular spring by 2.0 cm ...

Physics - If it requires 7.0 of work to stretch a particular spring by 2.1 from ...