Homework Help: Chemistry

Posted by Jan on Friday, November 16, 2012 at 10:18pm.

A common laboratory reaction is the neutralization of an acid with a base. When 50.0 mL of the .500 M HCl at 25 C is assed to 50 mL of .500 M NaOH at 25 C in a coffee cup calorimeter, the temperature of the mixture rises to 28.2 C. What is the heat of reaction per mole of acid? Assume the mixture has a specific heat capacity of 4.18 J/gK and that the densities of the reactant solutions are both 1.00 g/mL

Chemistry - DrBob222, Friday, November 16, 2012 at 10:29pm
q = heat released = [mass H2O x secific heat H2O x (Tfinal-Tinitial)]

mols of rxn = 0.5M x 0.050 L = 0.025 mols.
q/0.025 = delta H in J/mol. Usually this is quoted in kJ/mol so divide by 1000 for kJ/mol.
Chemistry - abood, Monday, April 15, 2013 at 1:16pm
912

Answer this Question

Related Questions

Chemistry - In an acid-base neutralization reaction 28.74 mL of 0.500 M ...
chemistry - The enthalpy of neutralization for the reaction of a strong acid ...
CHEMISTRY - The enthalpy of neutralization for the reaction of a strong acid ...
CHEMISTRY - The enthalpy of neutralization for the reaction of a strong acid ...
Chemistry - Calculate the molar heat of neutralization in kJ/mol of the reaction...
chemistry - Calculate the molar heat of neutralization in kJ/mol of the reaction...
Chemistry - 44.70 ml of 0.100 M NaOH are required to completely neutralize 50.00...
Chemistry - In the following acid—base neutralization reaction HNO3(aq)+ ...
CHEMISTRY-Explanation Please - In the laboratory, 3.50 grams of salicylic acid ...
Chemistry - A student titrates HCl with 0.0125M KOH. Starting with 50.00 ml of ...

For Further Reading

First Name:
School Subject:
Answer: