An investor invested a total of $500 in two mutual funds. One fund earned a 8% profit while the other earned a 4% profit. If the investor's total profit was $32, how much was invested in each mutual fund? The amount invested in the mutual fund that earned 8% was? The amount invested in the mutual fund that earned 4% was?

if x at 8%, then 500-x at 4%

adding up the interest,

.08x + .04(500-x) = 32.00
x = 300

so,
$300 @ 8%
$200 @ 4%

To find the amounts invested in each mutual fund, we can use a system of linear equations.

Let's assume the amount invested in the mutual fund that earned a 8% profit is x dollars, and the amount invested in the mutual fund that earned a 4% profit is y dollars.

From the given information, we know that the total amount invested is $500, and the total profit is $32.

So we have two equations:

1) x + y = $500 (equation for the total amount invested)
2) 0.08x + 0.04y = $32 (equation for the total profit)

To solve this system of equations, we can use the substitution method or the elimination method. Let's use the substitution method:

From equation 1) we can rewrite it as x = $500 - y.

Now substitute this expression for x in equation 2):

0.08($500 - y) + 0.04y = $32

Simplify the equation:

40 - 0.08y + 0.04y = $32
40 - 0.04y = $32

Subtract 40 from both sides:

-0.04y = -$8

Divide by -0.04:

y = $200

Now substitute the value of y back into equation 1) to find x:

x + $200 = $500
x = $300

Therefore, the amount invested in the mutual fund that earned 8% is $300, and the amount invested in the mutual fund that earned 4% is $200.