HELP !!! Algebra 2
posted by Robert .
15. What is the solution of the linearquadratic system of equations?
{y = x^2 + 5x  3}
{y  x = 2}

Try substituting those values, and you will see they do not fit either equation.
looking at the 2nd equation, y = x+2, so
x+2 = x^2+5x3
x^2 + 4x  5 = 0
(x+5)(x1) = 0
x = 5 or 1
so, y = 3 or 3
the solutions are thus (5,3)(1,3) 
first things first...calm down. yes, its extremely hard. but we go simple approach. yx=2 implies y=x+2.we substitute that in the first equation to get x+2 = x^2+5x3 =x^2+4x5=0.
We factor to get (x1)(x+5)=0. Thus, x=1, or 5. PLugging in, we get y=3,3. Thus, (1,3)(5,3) are the solutions