Posted by **Robert** on Friday, November 16, 2012 at 1:48pm.

15. What is the solution of the linear-quadratic system of equations?

{y = x^2 + 5x - 3}

{y - x = 2}

- HELP !!! Algebra 2 -
**Steve**, Friday, November 16, 2012 at 2:34pm
Try substituting those values, and you will see they do not fit either equation.

looking at the 2nd equation, y = x+2, so

x+2 = x^2+5x-3

x^2 + 4x - 5 = 0

(x+5)(x-1) = 0

x = -5 or 1

so, y = -3 or 3

the solutions are thus (-5,-3)(1,3)

- HELP !!! Algebra 2 -
**mathgeekdude**, Friday, November 16, 2012 at 5:19pm
first things first...calm down. yes, its extremely hard. but we go simple approach. y-x=2 implies y=x+2.we substitute that in the first equation to get x+2 = x^2+5x-3 =x^2+4x-5=0.

We factor to get (x-1)(x+5)=0. Thus, x=1, or -5. PLugging in, we get y=-3,3. Thus, (1,3)(-5,-3) are the solutions

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