Posted by **Britney** on Friday, November 16, 2012 at 1:15pm.

The quantity demanded each month of the Sicard wristwatch is related to the unit price given by the equation below, where p is measured in dollars and x is measured in units of a thousand. To yield a maximum revenue, how many watches must be sold? (Round your answer to the nearest whole number.)

P=41/0.01X^2+1 (0(less than or equal to)x(less than or equal to)20)

? watches

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**Steve**, Friday, November 16, 2012 at 2:40pm
revenue = quantity * price

r(x) = x*p(x)

= 41x/(0.01x^2+1)

dr/dx = (41-.41x^2)/(.01x^2+1)^2

since the denominator is never 0,

max revenue occurs where

(41-.41x^2) = 0

x = 10

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**Britney**, Friday, November 16, 2012 at 2:53pm
that wasnt right

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**Steve**, Friday, November 16, 2012 at 3:10pm
sorry - can you show me my mistake?

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**Britney**, Friday, November 16, 2012 at 4:26pm
idk...it jus said that it was wrong....but when i worked it out i got the same answer as you.

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