Posted by Britney on Friday, November 16, 2012 at 1:15pm.
The quantity demanded each month of the Sicard wristwatch is related to the unit price given by the equation below, where p is measured in dollars and x is measured in units of a thousand. To yield a maximum revenue, how many watches must be sold? (Round your answer to the nearest whole number.)
P=41/0.01X^2+1 (0(less than or equal to)x(less than or equal to)20)
? watches

math  Steve, Friday, November 16, 2012 at 2:40pm
revenue = quantity * price
r(x) = x*p(x)
= 41x/(0.01x^2+1)
dr/dx = (41.41x^2)/(.01x^2+1)^2
since the denominator is never 0,
max revenue occurs where
(41.41x^2) = 0
x = 10

math  Britney, Friday, November 16, 2012 at 2:53pm
that wasn't right

math  Steve, Friday, November 16, 2012 at 3:10pm
sorry  can you show me my mistake?

math  Britney, Friday, November 16, 2012 at 4:26pm
idk...it jus said that it was wrong....but when i worked it out i got the same answer as you.
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