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The quantity demanded each month of the Sicard wristwatch is related to the unit price given by the equation below, where p is measured in dollars and x is measured in units of a thousand. To yield a maximum revenue, how many watches must be sold? (Round your answer to the nearest whole number.)

P=41/0.01X^2+1 (0(less than or equal to)x(less than or equal to)20)

? watches

  • math - ,

    revenue = quantity * price
    r(x) = x*p(x)
    = 41x/(0.01x^2+1)

    dr/dx = (41-.41x^2)/(.01x^2+1)^2
    since the denominator is never 0,
    max revenue occurs where
    (41-.41x^2) = 0
    x = 10

  • math - ,

    that wasn't right

  • math - ,

    sorry - can you show me my mistake?

  • math - , jus said that it was wrong....but when i worked it out i got the same answer as you.

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