Homework Help: Statistics

Posted by Blerp on Friday, November 16, 2012 at 11:36am.

A study conducted by an airline showed that a random sample of nine of its passengers disembarking at the Cleveland airport, took an average of 24.1 minutes to claim their luggage. From a previous survey it was willing to assume that time to claim luggage is normally distributed with a variance of 18 (min)2. A 95% confidence interval for the mean time to claim one's luggage has endpoints.

24.1 ą 8.32

24.1 ą 3.92

24.1 ą 2.77

24.1 ą 3.26

24.1 ą 9.78

Statistics - MathGuru, Friday, November 16, 2012 at 7:05pm
CI95 = mean ą 1.96(sd/√n)

Substitute the values given into the formula to choose your answer.

Note: standard deviation is the square root of the variance.

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