Posted by lef on .
ICl2F+2: Calculate the maximum wavelength of electromagnetic radiation that is capable of breaking the weakest bond. Express your answer in meters.
Bond energies (kJ/mol) are:
II (150)
FF (160)
ClCl (240)

science 
Jorge,
I came up with:
EIF = 0.5[EII + EFF] + (χF – χI)2
EIF = 0.5[1.5546+ 1.6583] + (3.98 – 2.66)2
Solving this gives
EIF = 3.34885 eV = 323 kJ/mol
Similarly EClF = 265 kJ/mol and
EICl = 219 kJ/mol
So to break the ICl bond,
Wavelength of radiation= 6.625x10^34 Js x 3x10^8 m⁄s/2.19x10^3 J x6.023 x 10^23 = 5.47 x 10^5 m
Not ... not sure if this is 100% correct ... the result will change depending on decimals. What was your result? 
science 
N... ;),
Correct answer is:
1)
E ICl = sqrt(150X240) + 96.3 (2.663.16)^2
2)
E in kJ/mole > E in J/bond:
E ICl/ 6.02*10^23
3)
Wavelength = (6.626*10^(34) X 3*10^8) / (E in J/bond)
:))