Friday

November 21, 2014

November 21, 2014

Posted by **janice** on Friday, November 16, 2012 at 6:28am.

A = 115.2¡ã, a = 43.6 cm, b = 23.1 cm

First triangle (assume B ¡Ü 90¡ã):

B

=

¡ã

C

=

¡ã

c

=

cm

Second triangle (assume B' > 90¡ã):

B'

=

¡ã

C'

=

¡ã

c'

=

cm

- trig -
**Henry**, Sunday, November 18, 2012 at 9:35pmI am not familiar with your symbols.

sinB/b = sinA/a.

sinB/23.1 = sin115.2/43.6

Multiply both sides by 23.1

sinB = 23.1*sin115.2/43.6 = 0.47939

B = 28.6o.

CosA = b^2+c^2-a^2/2bc.

Cos115.2 = (23.1)^2+c^2-(43.6)^2/46.2c

-0.42578 = (533.61+c^2-1901)/46.2

-0.42578 = (-1367.39+c^2)/46.2c

-0.42578c = (-1367.39+c^2)/46.2

-19.67c = -1367.39+c^2

-c^2-19.67c = -1367.39

c^2+19.67c-1367.39 = 0.

c = 28.43 cm.

C = 180-115.2 -28.6 = 36.2o

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