Sunday

April 20, 2014

April 20, 2014

Posted by **eav** on Friday, November 16, 2012 at 6:18am.

- calculus -
**Steve**, Friday, November 16, 2012 at 10:42amif the height of the rectangle is y, the base of the rectangle is (20-y)/3 - y.

So, the area is y((20-y)/3 - y) = 4/3 (5y-y^2)

max area where 5-2y = 0, or y = 5/2.

So, the largest rectangle has area 50/3

**Related Questions**

Calculus - Hello, could someone please help me with this problem? I'm a little ...

Calculus - I have to find the area of the largest possible rectangle that can be...

Calculus - A rectangle in the first quadrant has one vertex as the origin, and ...

Calculus - A rectangle in the first quadrant has one vertex as the origin, and ...

Calculus - "A rectangle is inscribed in a semicircle of radius 2 cm. Find the ...

calculus - A rectangle with its base on the x-axis is to be inscribed under the ...

Math - The first question is this: Helen designs a rectangle with an area of 225...

calculus - A rectangle with its base on the x-axis is to be inscribed under the ...

calculus - Construct a window in the shape of a semi-circle over a rectangle.If ...

Calculus - 3) Consider rectangles located as shown in the first quadrant and ...