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September 3, 2014

September 3, 2014

Posted by **eav** on Friday, November 16, 2012 at 6:18am.

- calculus -
**Steve**, Friday, November 16, 2012 at 10:42amif the height of the rectangle is y, the base of the rectangle is (20-y)/3 - y.

So, the area is y((20-y)/3 - y) = 4/3 (5y-y^2)

max area where 5-2y = 0, or y = 5/2.

So, the largest rectangle has area 50/3

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