Posted by Leyla on Thursday, November 15, 2012 at 9:05pm.
let's assume the growth of bacteria is "almost" continuous
so number = initial value e^(kt) where k is a constant
so 12000 e^(1k) = 25000
e^k = 2.0833333...
k = ln 2.083333.. =.733969
number after 3 hrs = 12000 e^(3(.733969)) = 108506.9 or
109,000 to the nearest thousand
Related Questions
Calc - The number of bacteria in a culture is increasing according to the law of...
precalculus - A bacteria culture initially contains 1500 bacteria and doubles ...
MATH :) - 3. In Biology, it is found that the bacteria in a certain culture ...
calculus - 2. The rate of change in the number of bacteria in a culture is ...
pre calculus - if there are initial 2500 bacteria in a culture, and the number ...
Algebra 2 - If there are initially 1500 bacteria in a culture, and the number of...
math - The number of bacteria in a culture is modeled by: n(t) = 1330e^(0.42t) (...
Math - he number of bacteria in a culture is modeled by n(t)=1710e071t (a) The ...
math - The number of bacteria in a culture is modeled by n(t)=1710e071t (a) The ...
Calculus - A bacteria culture contains 200 cells initially and grows at a rate ...
For Further Reading