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November 23, 2014

November 23, 2014

Posted by **Leyla** on Thursday, November 15, 2012 at 9:05pm.

- Math -
**Reiny**, Thursday, November 15, 2012 at 9:45pmlet's assume the growth of bacteria is "almost" continuous

so number = initial value e^(kt) where k is a constant

so 12000 e^(1k) = 25000

e^k = 2.0833333...

k = ln 2.083333.. =.733969

number after 3 hrs = 12000 e^(3(.733969)) = 108506.9 or

109,000 to the nearest thousand

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