Wednesday

January 28, 2015

January 28, 2015

Posted by **Leyla** on Thursday, November 15, 2012 at 9:05pm.

- Math -
**Reiny**, Thursday, November 15, 2012 at 9:45pmlet's assume the growth of bacteria is "almost" continuous

so number = initial value e^(kt) where k is a constant

so 12000 e^(1k) = 25000

e^k = 2.0833333...

k = ln 2.083333.. =.733969

number after 3 hrs = 12000 e^(3(.733969)) = 108506.9 or

109,000 to the nearest thousand

**Answer this Question**

**Related Questions**

Calc - The number of bacteria in a culture is increasing according to the law of...

precalculus - A bacteria culture initially contains 1500 bacteria and doubles ...

Pre-Calc/Trig... - is this the correct formula for me to solve this? A bacteria ...

MATH :) - 3. In Biology, it is found that the bacteria in a certain culture ...

Algebra 2 - If there are initially 1500 bacteria in a culture, and the number of...

calculus - 2. The rate of change in the number of bacteria in a culture is ...

pre calculus - if there are initial 2500 bacteria in a culture, and the number ...

math - The number of bacteria in a culture is modeled by: n(t) = 1330e^(0.42t) (...

Math - he number of bacteria in a culture is modeled by n(t)=1710e071t (a) The ...

math - The number of bacteria in a culture is modeled by n(t)=1710e071t (a) The ...