Posted by Deane on Thursday, November 15, 2012 at 7:32pm.
M = mols/L = 6.00E-3/16.0 = ? = (H^+)
pH = -log (H^+)
Then pH + pOH = pKw = 14
You know pH and pKw, solve for pOH and from that use pOH = -log(OH^-) and solve for OH^-
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