A bulletin board is 56 in wide and 36 in high. How many 3 1/2 in columns can be created?

She was telling you the equation to solve it 56 divided by 3.5 or 3/5

56 / 3.5 = ?

thank you

You're welcome.

To find out how many 3 1/2 inch columns can be created on a bulletin board that is 56 inches wide, we need to divide the width of the bulletin board by the width of each column.

The width of each column is 3 1/2 inches, which can be written as a mixed number or an improper fraction. If we convert it to an improper fraction, it becomes 7/2 inches.

Now, let's divide the width of the bulletin board (56 inches) by the width of each column (7/2 inches):

56 inches ÷ (7/2 inches)

To divide by a fraction, we can multiply by its reciprocal. In this case, the reciprocal of 7/2 is 2/7. So:

56 inches × (2/7)

To simplify this multiplication, we can cancel out common factors. The common factor here is 7:

(8 × 2) inches ÷ 1
16 inches

Therefore, you can create 16 columns of width 3 1/2 inches on a bulletin board that is 56 inches wide.

Idk if your a math teacher or something but your answers are wrong .