A tank initially contains 50 liters of water. A hose adds water to the tank at a rate of 2 liters per minute. Write a linear equation for the amount of water in the tank, W, liters in terms of t, minutes. Then use your equation to find how much water is in the tank after 20 minutes.

50+2(x)=L water in tank

50+2(20)=L water in tank
50+40=90L water in tank

To write a linear equation for the amount of water in the tank, we need to understand how the amount of water changes over time.

Since the hose adds water at a constant rate of 2 liters per minute, the amount of water in the tank increases linearly with time.

Let W represent the amount of water in the tank in liters, and t represent the time in minutes.

At the start, the tank initially contains 50 liters of water, so we have a starting point on the graph: (t=0, W=50).

The rate of water being added to the tank is 2 liters per minute. So for every minute that passes, the amount of water in the tank increases by 2 liters.

This means that the slope (rate of change) of the linear equation is 2.

The equation of a linear relationship is often expressed in the form y = mx + b, where m is the slope, and b is the y-intercept.

In this case, the equation for the amount of water in the tank is:

W = 2t + 50

To find out how much water is in the tank after 20 minutes, we simply substitute t = 20 into the equation:

W = 2(20) + 50
W = 40 + 50
W = 90

Therefore, after 20 minutes, there will be 90 liters of water in the tank.