Posted by **britney** on Thursday, November 15, 2012 at 1:23pm.

let f(x)=x^3+3x^2-2x+4

What are the critical values?

Where are the relative extrema, if they exist?

- math -
**Steve**, Thursday, November 15, 2012 at 1:45pm
critical values are values in the domain where f'(x) = 0

since f'(x) = 3x^2 + 6x - 1, the critical values would be (-3±2√3)/2

the extrema occur at the critical values.

- math -
**Steve**, Thursday, November 15, 2012 at 1:51pm
oops. f' = 3x^2 + 6x - 2.

extrema at x=(-3±√15)/3

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