Posted by **homeworkgenius** on Thursday, November 15, 2012 at 10:32am.

Three people play a game of "nonconformity": They each choose rock, paper, or scissors. If two of the three people choose the same symbol, and the third person chooses a different symbol, then the one who chose the different symbol wins. Otherwise, no one wins.

If they play 4 rounds of this game, all choosing their symbols at random, what's the probability that nobody wins any of the 4 games? Express your answer as a common fraction.

- math but also probability -
**K**, Monday, August 10, 2015 at 11:16pm
1/81

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