Posted by zamanofdoom on Thursday, November 15, 2012 at 10:30am.
A fair, sixsided die is rolled eight times, to form an eightdigit number. What is the probability that the resulting number is a multiple of 8? Express your answer as a common fraction.

counting and probability  Anonymous, Tuesday, July 21, 2015 at 11:30am
hg.kk

counting and probability  ASD, Friday, October 16, 2015 at 10:49pm
gidae

counting and probability  i need help too, Saturday, October 17, 2015 at 8:44pm
I need help 2
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counting and probability  BOB, Thursday, July 28, 2016 at 12:43pm
Total number of numbers using 16
= 6^8 = 1679616
For any number to be divisible by 8, its last 3 digits must be divisible by 8
but these last two digits must contain only the digits from 1 to 6, with no zeros.
possible cases are:
112 136 144 152
216 224 232 256 264
312 336 344 352
416 424 432 456 464
512 536 544 552
616 624 632 656 664
Hoping that I didn't miss any, I count 27
so the front 5 numbers could be anything
there are 6^5 or 7776 different front numbers, each of those could have 27 different last three numbers
so there are 7776x27 or 209952 which are divisible by 8
prob that a number is a multiple of 8
= 209952/1679616
26244/209952
= 6561/52488
= 1/8 < Very suspicious

counting and probability  existing, Tuesday, August 16, 2016 at 1:18pm
BOB is right.
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