if 500Watt of energy is supplied, how long does it take to heat up 100 cc of water from 20C to 75C?

Thank you for your assistance,

To determine the time it takes to heat up the water from 20°C to 75°C using 500 Watts of energy, we can use the formula:

Q = mcΔT

Where:
Q is the amount of heat energy required
m is the mass of the water (in grams)
c is the specific heat capacity of water (which is 4.18 J/g°C)
ΔT is the change in temperature (final temperature - initial temperature) in degrees Celsius

First, we need to convert the volume of water (100 cc) to mass using the density of water, which is approximately 1 gram per 1 cc. So, the mass (m) of the water is 100 grams.

Next, we calculate the amount of heat energy required to heat up the water:

Q = 100g * 4.18 J/g°C * (75°C - 20°C)

Q = 79,300 Joules

Now, we need to find the time (t) it takes to supply 79,300 Joules of energy at a constant rate of 500 Watts. We can use the equation:

Power (P) = Energy (E) / Time (t)

Rearranging the equation, we have:

t = E / P

Substituting the values:

t = 79,300 J / 500 W

t = 158.6 seconds

So, it will take approximately 158.6 seconds (or about 2 minutes and 39 seconds) to heat up 100 cc of water from 20°C to 75°C using 500 Watts of energy.