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March 27, 2015

March 27, 2015

Posted by **Leslie** on Thursday, November 15, 2012 at 12:48am.

- Physics - Astronomy -
**drwls**, Thursday, November 15, 2012 at 3:02amKepler's third law says that, for all objects orbiting the same large mass,

P^2/R^3 = constant

P is the period; R is the orbit radius.

If the moon's period is 3 times the ring gap object's period

[R(gap)/R(moon)]^3 = [P(gap)/P(moon)]^2 = 1/9

[R(gap)/R(moon)] = cube root of 1/9

- Physics - Astronomy -
**drwls**, Saturday, November 17, 2012 at 2:26am[R(gap)/R(moon)] = cube root of 1/9 = 0.481

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