Posted by **Andrew** on Wednesday, November 14, 2012 at 11:12pm.

if only digits 0,1,2,3,4,5,6, and 7 may be used find number of possibilites four digit numbers

- math -
**Alexa**, Wednesday, November 14, 2012 at 11:17pm
n!/r!(n-r)!

8!/4!(8-4)!

= 70

- math -
**Reiny**, Wednesday, November 14, 2012 at 11:18pm
Ok, Andrew

in my last answer to the same question I somehow missed the 7 and saw only 6 numbers.

(Have to concentrate more on reading the question more carefully)

In each case we can assume that no whole number starts with a zero, and no repeating digits for all 3 cases.

We have 8 digits, but can only use 7 in the first position ...

number of 4 digits numbers = 7x7x6x5 = 1470

number of 3 digit odd numbers, (must end in an odd) = 6x6x4 = 144

number of 3 digit numbers = 7x7x6 = 294

## Answer This Question

## Related Questions

- Math - Received answer to the following question from Jishka. (2469) Would you ...
- math - given the digits 0,1,2,3,4,5,6, and 7 find the number of possibilities in...
- Math Help Please - Would you please explain the steps you used to get the answer...
- math - using digits 1-9 only once, multiply a 3 digit by a 2 digit number and ...
- MATH - Need Answer to the Following Please: Using the 9 digits, 1, 2, 3, 4, 5, ...
- Math - Using the 9 digits, 1, 2, 3, 4, 5, 6,7, 8 and 9 you can arrange four ...
- Math Help Please - Can you Please explain the answer that I received of 2469? It...
- high school - Use the digits in the year 2010 and the operations +, -, x, ÷, ...
- Math - How many odd four-digit numbers, all of the digit different can be formed...
- Algebra - Middle School - Use the digits in the year 2010 and the operations...

More Related Questions