Posted by **ani** on Wednesday, November 14, 2012 at 10:21pm.

1)d/dx of cos4x/3-x^2(inculding quentient&chain rule)

2)sin^2x/1+cosx(same method)

- math -
**Reiny**, Wednesday, November 14, 2012 at 10:47pm
#1

y = cos 4x/(3-x^2)

dy/dx = ( (3-x^2)(-4sin 4x) - cos 4x (-2x) )/(3-x^2)^2

try the second one, let me know what you got

- math -
**Steve**, Thursday, November 15, 2012 at 12:20am
you might be surprised at the answer to #2, unless you note that

sin^2/(1+cos) = (1-cos^2)/(1+cos) = 1-cos

no need for quotient rule or chain rule here.

## Answer This Question

## Related Questions

- Calculus - Just got through with derivatives, power rule, and chain rule. I am ...
- Math, Calculus - Find the derivative of the function. y= xcosx - sinx What's the...
- Precalculus/Trig - I can't seem to prove these trig identities and would really ...
- calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...
- calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...
- calculus - Let z = ∫(e^sin(t)dt) from x to y a = x b = y I tried thinking ...
- calculus - Find dz/dy and dz/dx Let z = ∫e^(sin(t))dt from x to y a = x b...
- Math, derivatives - f(x) = x² + 2Cos²x, find f ' (x) a) 2(x+cos x) b) x - sin x ...
- calculus - Could someone check my reasoning? thanx Find the derivative of the ...
- Math-trigonometry - Several questions from my homework, any are appreciated. ...

More Related Questions