Posted by marcus on Wednesday, November 14, 2012 at 10:08pm.
Actually the lines given off by Na are a doublet; i.e., one at 5890 A and the other at 5896 A. But we won't quibble.
Convert 5890A to meters and substitute in
E = hc/wavelength.
Solve for E which will be joules per photon. That times 6.02E23 will give joules/mol and that x 1E-4 will give joules in 1E-4 mols. Convert that to kJ.
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