Posted by **Andrew** on Wednesday, November 14, 2012 at 9:54pm.

given the digits 0,1,2,3,4,5,6, and 7 find the number of possibilities in each category four digit numbers, odd three digit numbers and three digit numbers without repeating digits.

- math -
**Reiny**, Wednesday, November 14, 2012 at 10:09pm
In each case we can assume that no whole number starts with a zero, and no repeating digits for all 3 cases.

number of 4 digits numbers = 6x6x5x4 = 720

number of 3 digit odd numbers, (must end in an odd) = 5x5x3 = 75

number of 3 digit numbers = 6x6x5 = 180

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