Posted by **Andrew** on Wednesday, November 14, 2012 at 9:54pm.

given the digits 0,1,2,3,4,5,6, and 7 find the number of possibilities in each category four digit numbers, odd three digit numbers and three digit numbers without repeating digits.

- math -
**Reiny**, Wednesday, November 14, 2012 at 10:09pm
In each case we can assume that no whole number starts with a zero, and no repeating digits for all 3 cases.

number of 4 digits numbers = 6x6x5x4 = 720

number of 3 digit odd numbers, (must end in an odd) = 5x5x3 = 75

number of 3 digit numbers = 6x6x5 = 180

## Answer This Question

## Related Questions

- data management - from the digits 0,1,2,3,4,5,6,7,8,9 find the number of a) 4-...
- Data management - from the digits 0,1,2,3,4,5,6,7,8,9 find the number of a) 4-...
- Math. Explain - From the digits 1, 2, 3, and 4, how many positive integers are ...
- Math - How many odd four-digit numbers, all of the digit different can be formed...
- Math - How many different three-digit numbers can be written using the digits 4...
- MATH Trouble - I have no idea what this problem means: For how many two-digit ...
- math - Find a six-digit even number containing no zeros and no repeating digits ...
- Math - How many different three-digit numbers can be written using digits from ...
- Math problems Help Please!!!!!! - i am a four-digit number with the digits in ...
- Math problems - i am a four-digit number with the digits in order. my first two ...

More Related Questions