Posted by wan on Wednesday, November 14, 2012 at 9:35pm.
House P has students numbers
1 5 9 13 17 ........ (4n-3)
House Q has students numbers
2 6 10 14 ...... (4n-2)
etc
4n-3 = 66
4n = 69 --> no whole number solution
4n-2 = 66
4n = 68
n = 17 ----- Yeah
The 66th student is in house Q
or
make 4 columns
P...Q...R....S
1 .. 2 .. 2 .. 4
5 .. 6 .. 7 .. 8
9 .. 10 11 12
13 14 15 16
17 18 19 20
...
65 66 67 68
for P -- remainder of 1 when divided by 4
for Q -- remainder of 2 when divided by 4 ---- 66
for R -- remainder of 3 when divided by 4
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