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Posted by **wan** on Wednesday, November 14, 2012 at 9:35pm.

- MATH -
**Reiny**, Wednesday, November 14, 2012 at 10:29pmHouse P has students numbers

1 5 9 13 17 ........ (4n-3)

House Q has students numbers

2 6 10 14 ...... (4n-2)

etc

4n-3 = 66

4n = 69 --> no whole number solution

4n-2 = 66

4n = 68

n = 17 ----- Yeah

The 66th student is in house Q

or

make 4 columns

P...Q...R....S

1 .. 2 .. 2 .. 4

5 .. 6 .. 7 .. 8

9 .. 10 11 12

13 14 15 16

17 18 19 20

...

65 66 67 68

for P -- remainder of 1 when divided by 4

for Q -- remainder of 2 when divided by 4 ---- 66

for R -- remainder of 3 when divided by 4

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