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Posted by on Wednesday, November 14, 2012 at 7:04pm.

Find the point on the line 1x+7y-4=0 which is closest to the point (-4,-6)

  • Math - , Wednesday, November 14, 2012 at 7:17pm

    distance will be along the perpendicular. The line perpendicular will have a slope= 7 (negative reciprocal of slope of the curve)

    y=mx+b=7x+b but the point -4,-6) is on the line, so
    -6=-28+b, or b=22 check that

    finally, the curve and the line intersect, so
    y=-x/7+4/7
    y=7x+22
    solve for x, y.

    Now the distance formula

    distance=sqrt[(x+4)^2+(y+6)^2 using x,y above.

  • Math - , Wednesday, November 14, 2012 at 7:26pm

    isn't x,y above just -4,-6 ?
    what do i do with the distance formula?

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