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An aluminum bar has the desired length when at 10 degrees Celsius. How much stress is required to keep it at this length if the temperature increases to 33 degrees Celsius?

  • Physics - ,

    The change in L = (Initial L)x(Force)/E/Area.

    The change in L also = (Alpha)x(Initial L)x(Change in Temperature)

    So, (Alpha)x(Change in Temperature)x(E) = Force/Area

    So, (25x10^-6)x(23)x(70x10^9) = 4.0x10^7 N/m^2

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