Posted by Bobby on Wednesday, November 14, 2012 at 6:27pm.
The change in L = (Initial L)x(Force)/E/Area.
The change in L also = (Alpha)x(Initial L)x(Change in Temperature)
So, (Alpha)x(Change in Temperature)x(E) = Force/Area
So, (25x10^-6)x(23)x(70x10^9) = 4.0x10^7 N/m^2
Related Questions
Chemistry - the specific heat of aluminum is 0.900 J/g degrees celsius. how ...
PHYSICS 102E - 1. How much ice at -10 degrees Celsius is required to cool a ...
calculus - A cold metal bar at -30 degrees Celsius is submerged in a pool ...
Chemistry - Calculate the joules of energy involved when 11 grams of water at 10...
heat - A siler bar 0.125 meter long is subjected to a temperature change from ...
PHYSICS 102E - a brass ring of diameter 10.00cm at 20.0 degrees Celsius is ...
physics - An aluminum cube .100 m on a side is heated from 10 degrees Celsius to...
Physical Science - Hello, Can some one please tell me if I calcilater this right...
science - An aluminum bar is 2m long at a temperature of 20 degrees C What will ...
physics - An aluminum rod at 18 degrees Celsius has a length of 2.50 meters. At ...
For Further Reading