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April 1, 2015

April 1, 2015

Posted by **Bobby** on Wednesday, November 14, 2012 at 6:27pm.

- Physics -
**Bethany**, Wednesday, November 14, 2012 at 6:35pmThe change in L = (Initial L)x(Force)/E/Area.

The change in L also = (Alpha)x(Initial L)x(Change in Temperature)

So, (Alpha)x(Change in Temperature)x(E) = Force/Area

So, (25x10^-6)x(23)x(70x10^9) = 4.0x10^7 N/m^2

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