Post a New Question


posted by .

An arrow is shot at an angle such that it's horizontal velocity is 40 m/s and it's vertical velocity is 20 m/s. Find the horizontal distance the arrow will travel before hitting the ground

  • Physics -

    do vertical problem first to find time in the air which is twice the time going up
    v = Vi - g t
    0 at top = 20 - 9.8 t
    t = 20/9.8

    2 t = time in air = 40/9.8

    Now how far horizontal at constant speed of 40?
    40(40/9.8) = 1600/9.8
    or about 160 meters

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question