Homework Help: Chem help asap

Posted by Whitney on Wednesday, November 14, 2012 at 3:57pm.

A 890 mL NaCl solution is diluted to a volume of 1.15 and a concentration of 8.00 . What was the initial concentration?

How do I go about this?

M1V1=M2V2? and if it is how do I replace the variables?

Chem help asap - DrBob222, Wednesday, November 14, 2012 at 6:31pm
Probably M1V1 = M2V2 BUT you give no units. 1.15 what. concn of 8.00 what.
You call 890 V1 and M1 is what you want.
V2 is 1.15 whatever and 8.00 is M2 whatever. Since V1 is 890 mL you need V2 in mL. Whatever unit the 8.00 is will be that unit in M1.

Answer this Question

Related Questions

chemistry - 25.00 mL of a 2.00 M solution of NaCl is diluted to a final volume ...
chemistry - A stock solution of 0.0100 M KMnO4 is diluted by taking 15.5 mL of ...
chemistry - A 25.00 mL solution of potassium nitrate (KNO3) was diluted to 125.0...
chemistry - A 25.00 mL solution of potassium nitrate (KNO3) was diluted to 125.0...
Chemistry - If 12.90 mL of a 18.2 Weight% solution of sodium chloride is diluted...
Chemistry - What is the molarity of a solution of Mg(OH)2 if the solution ...
Chemistry - A volume of 25.0 mL of 8.0 M acetic acid is diluted with sufficient ...
molarity - An aspirin tablet weighing 0.475 g has been analyzed and contains 68....
Chem. - An aspirin tablet weighing 0.400 g has been analyzed and contains 68.2...
chem - An aspirin tablet weighing 0.650 g has been analyzed and contains 68.2 % ...

For Further Reading

First Name:
School Subject:
Answer: