Posted by **zach w** on Wednesday, November 14, 2012 at 3:20pm.

q(x)=3x^2-11x-4/5x^2-16x-16

what are the

oblique

horizontal

vertical asyptote

- college algebra -
**Reiny**, Wednesday, November 14, 2012 at 4:00pm
I assume you mean

q(x) = (3x^2 - 11x - 4)/(5x^2 - 16x - 16)

then

q(x) = (3x+1)(x-4)/( (5x+4)(x-4) )

= (3x+1)/(5x+4) , x ≠ 4

vertical asymptote : x = -4/5

horizontal ... : y = 3/5

no oblique

there is a "hole" at (4, 13/24)

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