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March 25, 2017

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q(x)=3x^2-11x-4/5x^2-16x-16
what are the
oblique
horizontal
vertical asyptote

  • college algebra - ,

    I assume you mean
    q(x) = (3x^2 - 11x - 4)/(5x^2 - 16x - 16)
    then
    q(x) = (3x+1)(x-4)/( (5x+4)(x-4) )
    = (3x+1)/(5x+4) , x ≠ 4

    vertical asymptote : x = -4/5
    horizontal ... : y = 3/5
    no oblique

    there is a "hole" at (4, 13/24)

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