Sunday
March 26, 2017

Post a New Question

Posted by on .

A 5.0g KBr sample, at 25 degrees celsius, dissolved in 25 ml of water, also at 25 degrees celsius. the final equilibrium temperature of the resulting solution is 18.1 degrees celsius, What is the enthalpy change in J/g and KJ/mole of KBr.

  • Chemistry - ,

    q = [mass H2O x specific heat H2O x (Tfinal-Tinitial)]
    Substitute and solve for q = delta H for the solution.
    q/5 = delta H/g in joules.
    delta (H/g) x molar mass KBr = J/mol.
    Convert to kJ/mol.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question