Physics
posted by Emily on .
A golf club strikes a 0.061kg golf ball in order to launch it from the tee. For simplicity, assume that the average net force applied to the ball acts parallel to the ballâ€™s motion, has a magnitude of 7760 N, and is in contact with the ball for a distance of 0.014 m. With what speed does the ball leave the club?

W= change in Kinetic Energy
F*s = 1/2mv^2
Solve by v:
v= sqrt((2Fs)/m))
substitution:
v= sqrt((2*7760N*0.014m)/0.061kg)
v=59.68 m/s