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March 31, 2015

March 31, 2015

Posted by **Angelica** on Wednesday, November 14, 2012 at 11:25am.

- College Algebra -
**Steve**, Wednesday, November 14, 2012 at 11:49amsince x^2 = y+7,

(y+7) + y^2 = 13

y^2 + y - 6 = 0

(y+3)(y-2) = 0

y = -3 or 2

so, x = ±2 or ±3

the solutions are

(-3,2)(3,2)(2,-3)(-2,-3)

How did you arrive at your results?

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