Posted by **Angelica ** on Wednesday, November 14, 2012 at 11:25am.

I am using Hawkes Learning System (8.7 Nonlinear Systems of Equations)and my problem is x^2+y^2=13 and y+7=x^2. The answers I came up with are 2 square root of 3 and 3 for my x's. And I received (5,-4) as the y-coordinates. Is this correct?

- College Algebra -
**Steve**, Wednesday, November 14, 2012 at 11:49am
since x^2 = y+7,

(y+7) + y^2 = 13

y^2 + y - 6 = 0

(y+3)(y-2) = 0

y = -3 or 2

so, x = ±2 or ±3

the solutions are

(-3,2)(3,2)(2,-3)(-2,-3)

How did you arrive at your results?

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