Posted by Angelica on Wednesday, November 14, 2012 at 11:25am.
since x^2 = y+7,
(y+7) + y^2 = 13
y^2 + y - 6 = 0
(y+3)(y-2) = 0
y = -3 or 2
so, x = ±2 or ±3
the solutions are
(-3,2)(3,2)(2,-3)(-2,-3)
How did you arrive at your results?
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