calulate the molality of solution that contains 51.2g C10H10 in 500mL of CCl4. the density of CCl4 is 1.6g/mL
To calculate the molality of a solution, you need to know the mass of the solute (in this case, C10H10) and the mass of the solvent (in this case, CCl4). The formula for molality (m) is given by:
m = moles of solute / mass of solvent in kg
Here's how you can find the molality of the solution:
Step 1: Calculate the moles of C10H10:
First, you need to convert the mass of C10H10 from grams to moles. To do this, divide the given mass of C10H10 by its molar mass. The molar mass of C10H10 can be calculated by adding up the atomic masses of each element in the compound (you can find this information on the periodic table).
C10H10 molar mass = (10*C) + (10*H)
= 120.16 g/mol
moles of C10H10 = mass of C10H10 / molar mass of C10H10
Step 2: Calculate the mass of CCl4:
The density of CCl4 is given as 1.6 g/mL. Since you have 500 mL of CCl4, you can multiply the density by the volume to get the mass of CCl4.
mass of CCl4 = density of CCl4 * volume of CCl4
Step 3: Convert the mass of CCl4 to kg:
Since the molality formula requires the mass of the solvent in kilograms, you need to convert the mass of CCl4 from grams to kilograms by dividing it by 1000.
mass of CCl4 in kg = mass of CCl4 / 1000
Step 4: Calculate the molality:
Now that you have the moles of C10H10 (solute) and the mass of CCl4 (solvent) in kilograms, you can apply the molality formula.
m = moles of C10H10 / mass of CCl4 in kg
By following these steps and substituting the calculated values, you can determine the molality of the solution containing 51.2 g of C10H10 in 500 mL of CCl4.