Homework Help: Stoichiometry

Posted by Mike on Wednesday, November 14, 2012 at 2:10am.

How many grams of oxygen are required to completely burn 85.6 grams of methane (CH4)?

CH4 + O2 → H2O + CO2

Stoichiometry - Steve, Wednesday, November 14, 2012 at 11:17am
85.6g CH4 = 5.34 moles
each mole CH4 reacts with 1 mole of O2
so, you need 5.34 moles O2 = 85.39g O2
Stoichiometry - Steve, Wednesday, November 14, 2012 at 11:17am
oops: O2 = 32, not 16, so that's 170.78g

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