Posted by **Alexis** on Tuesday, November 13, 2012 at 11:22pm.

Find the derivatives of these:

f(x)=(√(x))sinPix

Also:

f(x)=√(Cosx+sinx)

Steps would be greatly helpful as I will be able to use them as reference. Thank you.

- Maths -
**just walked by**, Tuesday, November 13, 2012 at 11:35pm
f'(x)=(√(x))'*(sin(pix))+(sin(pix))'*(√(x))=1/2*(x)^(-1/2)*(sin(pix))+cos(pix)*(pi)*(√(x))

2)

f'(x)=(1/2(cosx+sinx)^(-1/2))(cos(x)+sin(x))'=(1/2(cosx+sinx)^(-1/2)*(-sin(x)+cos(x))

- Maths -
**Steve**, Wednesday, November 14, 2012 at 10:51am
correct answers, but they're sort of like leaving an answer as 4x^2y/3xy instead of simplifying to 4x/3

1)1/2√x sinπx + π/√x cosπx

= 1/2√x (sinπx + 2πcosπx)

2)

(cosx-sinx) / 2√(cosx+sinx)

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