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December 18, 2014

December 18, 2014

Posted by **Patrick** on Tuesday, November 13, 2012 at 11:20pm.

- College Algebra -
**Steve**, Wednesday, November 14, 2012 at 10:34amf(x) = a(x-1)(x-(3+2i))(x-(3-2i))

= a(x-1)(x^2-6x+13)

= a(x^3-7x^2+19x-13

f(-1) = a(-1-7-19-13) = 40a = 2

so, a = 1/20

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