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December 19, 2014

December 19, 2014

Posted by **Daniella** on Tuesday, November 13, 2012 at 11:02pm.

- Calculus -
**Steve**, Wednesday, November 14, 2012 at 10:42amsince f' = e^x > 0, f(x) is always increasing.

So, on [a,b] min=e^a and max is e^b

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