How many grams of calcium carbonate, CaCO3, do you need in an antacid tablet to neutralize 20 mL of stomach acid? (stomach acid is 0.1 M HCl. There are 3.65g of HCl in 1L of stomach acid or 1g of HCl in 274g of stomach acid).
20ml solution (3.65/1000ml)(1mol hcl/36.4527gHcl)(1mol CaCo3/2molHCl) (100.0872 g CaCo3/1 mol CaCo3)= 0.1002g CaCo3
You have more information in the problem than you need.
Write the equation.
CaCO3 + 2HCl ==> CaCl2 + CO2
mols HCl = M x L = 0.1M x 0.020 L = ?
mols CaCO3 = 1/2 that (from the coefficients in the balanced equation).
Then grams CaCO3 = mols CaCO3 x molar mass CaCO3.
I didn't furnish the exact equation but it doesn't change anything in my answer.
CaCO3 + 2HCl ==> CaCl2 + CO2 + H2O
To find the number of grams of calcium carbonate (CaCO3) needed to neutralize 20 mL of stomach acid, we need to follow these steps:
Step 1: Convert the volume of stomach acid to moles of HCl.
Given that the stomach acid is 0.1 M HCl and the volume is 20 mL, we can use the formula:
moles = concentration (M) x volume (L)
Converting the volume to liters:
20 mL = 20 / 1000 L = 0.02 L
Now, we can calculate the moles of HCl:
moles = 0.1 M x 0.02 L = 0.002 moles HCl
Step 2: Convert moles of HCl to grams of HCl.
Given that there are 3.65 g of HCl in 1 L of stomach acid, we can use the formula:
grams = moles x molar mass
The molar mass of HCl is 36.5 g/mol.
grams = 0.002 moles HCl x 36.5 g/mol = 0.073 g HCl
Step 3: Convert grams of HCl to grams of stomach acid.
Given that there are 1 g of HCl in 274 g of stomach acid, we can use the formula:
grams of stomach acid = grams of HCl x (1/0.073)
grams of stomach acid = 0.073 g HCl x (1/0.073) = 1 g stomach acid
Step 4: Convert grams of stomach acid to grams of CaCO3.
Given that the stoichiometric ratio between HCl and CaCO3 is 1:1 (from the balanced chemical equation), we can say that 1 g of stomach acid will be neutralized by 1 g of CaCO3.
Therefore, the number of grams of CaCO3 needed is 1 g.
So, you would need 1 gram of calcium carbonate (CaCO3) in an antacid tablet to neutralize 20 mL of stomach acid.