a plane flys 350 km south along a straight path with an average velocity of 125 km/h to the south. the plane has a 30 minute layover and then travels 220 km south with an average velocity of 115 km/h to the south. what is the average velocity of the trip
avg velocity=displacement/time
displacement=350S+220S
time=350/125+.5+220/115
To find the average velocity of the trip, we need to consider both the distance traveled and the total time taken.
Let's break down the problem into two parts:
Part 1: Plane flies 350 km south with an average velocity of 125 km/h.
Distance traveled in Part 1 = 350 km
Time taken in Part 1 = Distance / Velocity = 350 km / 125 km/h = 2.8 hours
Part 2: Plane travels 220 km south with an average velocity of 115 km/h.
Distance traveled in Part 2 = 220 km
Time taken in Part 2 = Distance / Velocity = 220 km / 115 km/h = 1.91 hours
Now, let's calculate the total distance and total time for the entire trip.
Total distance = Distance traveled in Part 1 + Distance traveled in Part 2 = 350 km + 220 km = 570 km
Total time = Time taken in Part 1 + Time taken in Part 2 = 2.8 hours + 1.91 hours = 4.71 hours
Finally, we can calculate the average velocity of the trip by dividing the total distance by the total time:
Average velocity = Total distance / Total time = 570 km / 4.71 hours = 120.93 km/h
Therefore, the average velocity of the entire trip is approximately 120.93 km/h.