Posted by stacy on .
given 2C6H6+15O2>12CO2+6H2O
1. Starting with a confined volume of 4.80L and O2 with a partial pressure of 223.1 torr at 25 degrees C. C6H6 is in excess. The reaction is allowed to proceed to completion. The container is returned to 25C. Both liquid water and benzene are now present. The vapor pressure for benzene is 96.0 torr at 25C and vapor pressure of water at 25C is 24.0 torr. Calculate the total pressure. (you first need to calculate the CO2 pressure, which is its partial pressure)

chemistry 
DrBob222,
Use PV = nRT and solve for n = mols O2.
Convert mols O2 to mols CO2 and mols H2O
Use PV = nRT and convert mols CO2 to pressure. I would then convert pCO2 in atm to torr.
Ptotal = pCO2 + pH2O + pC6H6.
Post your work if you get stuck.