Posted by **Eliza** on Tuesday, November 13, 2012 at 10:45am.

If you had 106.35 grams of Cl, how much Na would be required to convert i all to NaCl. I worked this problem and got 41.83 grams of Na, but I'm not sure if this is correct.

- chemistry (molecular calculations) -
**DrBob222**, Tuesday, November 13, 2012 at 5:18pm
The quick way is to use a chemical factor but that isn't taught anymore in chemistry classes. It would be

106.35 x (atomic mass Na/atomic mass Cl) = 69.00 g Na.

The modern, and long way around is this.

(106.35/atomic mass Cl) = mols Cl

Convert to mols Na by

mols Cl x (1 mol Na/1 mol Cl)

Convert mols Na to g Na by

g Na = mols Na x (atomic mass Na/1 mol Na)

Put together this becomes

(106.35g/atomic mass Cl) x (1 mol Na/1 mol Cl) x (atomic mass Na/1 mol Na) =

(106.35/35.45) x (1/1) x (23/1) = 69.00

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