Posted by **James** on Tuesday, November 13, 2012 at 10:08am.

Find an equation of the tangent line to the curve for the given value of t.

x=t^2-2t, y=t^2+2t when t=1

- Calculus -
**Reiny**, Tuesday, November 13, 2012 at 10:28am
dx/dt = 2t-2

dy/dt = 2t+2

when t=1

slope = dy/dx = (dy/dt) / (dx/dt) = 4/0 , ahhh, a vertical line

when t=1

x = 1-2 = -1

y = 1 + 2 = 3

so a vertical line through (-1,2) is

x = -1

## Answer this Question

## Related Questions

- Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
- Calculus - Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2y-x...
- AP AB Calculus - Linear approximation: Consider the curve defined by -8x^2 + 5xy...
- calculus - find the equation of the tangent line at the given value of x on the ...
- calculus - a. find an equation for the secant line through the points where x ...
- Calculus - Find the equation of the tangent line to the curve at the given value...
- maths - given the equation of the curve as y=8-2x^2 (a) find equations of ...
- calculus - Find an equation of the tangent(s) to the curve at a given point. ...
- Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...
- Calculus - Use the given equation to answer the following questions. (Enter your...