Posted by **James** on Tuesday, November 13, 2012 at 10:08am.

Find an equation of the tangent line to the curve for the given value of t.

x=t^2-2t, y=t^2+2t when t=1

- Calculus -
**Reiny**, Tuesday, November 13, 2012 at 10:28am
dx/dt = 2t-2

dy/dt = 2t+2

when t=1

slope = dy/dx = (dy/dt) / (dx/dt) = 4/0 , ahhh, a vertical line

when t=1

x = 1-2 = -1

y = 1 + 2 = 3

so a vertical line through (-1,2) is

x = -1

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