Posted by **Greg** on Tuesday, November 13, 2012 at 9:45am.

Draw and solve any triangles satisfying

alpha = 29 degrees

a = 7

c = 14

I realize I need to draw a non-right triangle and label the sides but I am completely confused one what to do after I draw the triangle

- Precalc/Triangles -
**Reiny**, Tuesday, November 13, 2012 at 10:17am
Unless you were told to do so, why must it be right-angled

e.g. triangle ABC , were a=7, c=14 and angle A = 29°

(assuming you are using the convention of labeling the vertices with captital letters and the sides opposite with small letters

by Sine Law

SinC/14 = sin29/7

sinC = 14sin29/7 = .96961..

angle C = 75.8°

then angle B = 180-29-75.8 = 75.2°

and once again:

b/sinB = a/sinA

b/sin75.2 = 7/sin29

b = 13.96

(notice the triangle is "almost" isosceles)

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