Precalc/Triangles
posted by Greg on .
Draw and solve any triangles satisfying
alpha = 29 degrees
a = 7
c = 14
I realize I need to draw a nonright triangle and label the sides but I am completely confused one what to do after I draw the triangle

Unless you were told to do so, why must it be rightangled
e.g. triangle ABC , were a=7, c=14 and angle A = 29°
(assuming you are using the convention of labeling the vertices with captital letters and the sides opposite with small letters
by Sine Law
SinC/14 = sin29/7
sinC = 14sin29/7 = .96961..
angle C = 75.8°
then angle B = 1802975.8 = 75.2°
and once again:
b/sinB = a/sinA
b/sin75.2 = 7/sin29
b = 13.96
(notice the triangle is "almost" isosceles)