Posted by Greg on Tuesday, November 13, 2012 at 9:45am.
Unless you were told to do so, why must it be right-angled
e.g. triangle ABC , were a=7, c=14 and angle A = 29°
(assuming you are using the convention of labeling the vertices with captital letters and the sides opposite with small letters
by Sine Law
SinC/14 = sin29/7
sinC = 14sin29/7 = .96961..
angle C = 75.8°
then angle B = 180-29-75.8 = 75.2°
and once again:
b/sinB = a/sinA
b/sin75.2 = 7/sin29
b = 13.96
(notice the triangle is "almost" isosceles)
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