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September 1, 2014

September 1, 2014

Posted by **Ama** on Tuesday, November 13, 2012 at 7:35am.

cos u + sin u tan u

- precalculus -
**Damon**, Tuesday, November 13, 2012 at 8:05amcos u + sin u (sin u/cos u)

cos u + sin^2 u / cos u

cos^2u/cos u + sin^2 u/cos u

(cos^2 u + sin^2 u) / cos u

1/cos u

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