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January 21, 2017
Posted by **Ama** on Tuesday, November 13, 2012 at 7:27am.

y2 = 8x

- precalculus -
**Henry**, Friday, November 16, 2012 at 12:09amThis is an X-parabola.

Y^2 = 8x.

X = (1/8)y^2

k = Yv = -b/2a = 0/(1/4) = 0

h = Xv = (1/8*0^2 = 0.

V(h,k) = V(0,0).

D(X1,K), V(h,k), F(X2,K).

D(X1,0), V(0,0), F(X2,0).

DV = 0-X1 = 1/4a.

0-X1 = 1/(1/2) = 2.

X1 = -2.

VF = X2-0 = 1/4a

X2 = 1/(1/2) = 2

Focal Dia.(Ver. line).

A(2,Y1), F(2,0), B(2,Y2).

a = 1/8

1/a = 8 = Focal Dia.

AF = 0-Y1 = 8/2 = 4.

Y1 = -4.

FB = Y2-0 = 8/2 = 4

Y2 = 4.