1.)A sample of ammonium nitrate contains 70 g of nitrogen.what is the mass of the sample?

2.)no. of gram atom of ca in 100 g of caco3(mol.wt. of caco3=100g)

tiko+carbon=h2o

1. 201.0g

To find the mass of the sample of ammonium nitrate, we need to first determine the molar mass of ammonium nitrate (NH4NO3).

1) Calculate the molar mass of ammonium nitrate:
The molar mass of nitrogen (N) is 14 g/mol, and the molar mass of oxygen (O) is 16 g/mol. The molar mass of hydrogen (H) is 1 g/mol.
NH4NO3 contains 1 nitrogen atom, 4 hydrogen atoms, and 3 oxygen atoms.

Molar mass of NH4NO3 = (1 * molar mass of N) + (4 * molar mass of H) + (3 * molar mass of O)
= (1 * 14 g/mol) + (4 * 1 g/mol) + (3 * 16 g/mol)
= 14 g/mol + 4 g/mol + 48 g/mol
= 66 g/mol

2) Calculate the mass of the sample:
Since the sample contains 70 g of nitrogen, we can use the molar mass to convert from grams of nitrogen to grams of NH4NO3.

Mass of the sample of ammonium nitrate = (70 g / 1 mol) * (1 mol / 66 g)
= 70/66 g
≈ 1.06 g

Therefore, the mass of the sample of ammonium nitrate is approximately 1.06 g.

For the second question:
To determine the number of gram atoms of calcium (Ca) in 100 g of calcium carbonate (CaCO3), we need to calculate the number of moles of calcium and then convert it to gram atoms.

1) Calculate the molar mass of calcium carbonate:
The molar mass of calcium (Ca) is 40 g/mol, the molar mass of carbon (C) is 12 g/mol, and the molar mass of oxygen (O) is 16 g/mol.
CaCO3 contains 1 calcium atom, 1 carbon atom, and 3 oxygen atoms.

Molar mass of CaCO3 = (1 * molar mass of Ca) + (1 * molar mass of C) + (3 * molar mass of O)
= (1 * 40 g/mol) + (1 * 12 g/mol) + (3 * 16 g/mol)
= 40 g/mol + 12 g/mol + 48 g/mol
= 100 g/mol

2) Calculate the number of moles of calcium:

Moles of Ca = (100 g / 100 g/mol)
= 1 mol

3) Convert moles to gram atoms:
Since 1 mole of any element contains 6.022 x 10^23 atoms, we can use this conversion factor to find the number of gram atoms.

Number of gram atoms of Ca = 1 mol * (6.022 x 10^23 gram atoms/mol)
≈ 6.022 x 10^23 gram atoms

Therefore, there are approximately 6.022 x 10^23 gram atoms of calcium in 100 g of calcium carbonate.

Damn.. I wanted the answer