A 5ml, 10ml, 15 ml, and 20ml Aliquot of 0.010 M sodium salicylate solution was diluted to 100 ml in four different 100ml volumetric flasks with the iron (III)Chloride solution. What are their concentrations.
You diluted the first one from 5 mL to 100 mL; therefore, the new concn will be = 0.01 M x (5 mL/100 mL) = ?M
Or you can say you diluted it by a factory of 100/5 = 20 times; therefore, it is 1/20th as strong.
Then 0.01 x 1/20 = ?
Thankyou Dr. Bob also on my other question I am not sure how to get the heat capacity of NH4Cl to calculate molar enthalpy and I also don't know how to determine the concentration of NH4Cl inside the calorimeter. Please help me on that question as well and thankyou soo much.
To determine the concentrations of the diluted solutions, we need to consider the dilution factor. The dilution factor is the ratio of the final volume of the solution to the initial volume.
From the given information, we know that each aliquot (5ml, 10ml, 15ml, and 20ml) was diluted to a final volume of 100ml. Therefore, the dilution factor for each aliquot is:
Dilution factor = Final volume / Initial volume
For example, let's calculate the dilution factor for the 5ml aliquot:
Dilution factor = 100ml / 5ml = 20
Now, the concentration of the diluted solution can be calculated using the following formula:
Concentration of diluted solution = Concentration of initial solution / Dilution factor
Given that the initial concentration of the sodium salicylate solution is 0.010 M, let's calculate the concentration of the diluted solutions for each aliquot:
For the 5ml aliquot:
Concentration = 0.010 M / 20 = 0.0005 M
For the 10ml aliquot:
Concentration = 0.010 M / 10 = 0.001 M
For the 15ml aliquot:
Concentration = 0.010 M / 6.67 = 0.0015 M
For the 20ml aliquot:
Concentration = 0.010 M / 5 = 0.002 M
Therefore, the concentrations of the diluted solutions are as follows:
- 5ml aliquot: 0.0005 M
- 10ml aliquot: 0.001 M
- 15ml aliquot: 0.0015 M
- 20ml aliquot: 0.002 M