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March 29, 2015

March 29, 2015

Posted by **Ravinder** on Monday, November 12, 2012 at 11:31pm.

- math -
**Reiny**, Monday, November 12, 2012 at 11:38pmAt a time of t minutes, let the

radius of the water level be r

let the height of the water be h

by ratio:

r/h = 8/9

r = 8h/9

V = (1/3)π r^2 h

= (1/3)π(64h^2/81)h

= (64π/243) h^3

dV/dt = (64π/81) h^2 dh/dt

6 = (64π/81) (9) dh/dt

I will let you solve for dh/dt

- math -
**Ravinder**, Monday, November 12, 2012 at 11:41pmthanks so much!

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