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Posted by on Monday, November 12, 2012 at 10:00pm.

Naoh (aq) + HCl (aq) --> NaCl (aq) + H2O (l)
Using the dT determined in part 1, calculate the heat capacity of the calorimeter. Enthalpy of reaction= -58.3 kj/mol, Cs (NaCl = 3.91j/g C)density of 1 M NaCl = 1.037g/mL. dT= 12.88 degrees Celcius.

  • Chemistry - , Monday, November 12, 2012 at 10:06pm

    50 mL of 2.00 M HCl and 50 ml of 2.05 M NaOH were used

  • Chemistry - , Monday, November 12, 2012 at 10:11pm

    See your other post below.

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