Posted by **Kay** on Monday, November 12, 2012 at 9:56pm.

I form a 3-digit number at random from the digits 1-9. What is the probability that my number has no repeated digits? All three digits the same? Exactly one repeated digit?

- Math -
**Kay**, Monday, November 12, 2012 at 10:34pm
please?

- Math -
**Reiny**, Monday, November 12, 2012 at 11:46pm
number of cases with no repeating digits

= 9x8x7 = 504

number of cases where digits repeat

= 9x9x9 = 729

so prob(no repeating digits) = 504/729 = 56/81

all 3 digits repeat, could be 111 , 222, .. 999

or 9 of them

prob = 9/729 = 1/81

I am not clear what you mean by "exactly one repeated digit"

- Math -
**Kay**, Tuesday, November 13, 2012 at 12:11am
one digit is repeated twice

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