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Posted by **Elise** on Monday, November 12, 2012 at 12:48pm.

- algebra -
**Reiny**, Monday, November 12, 2012 at 1:02pmnumber of tens -- x

number of fives -- y

number of ones -- 38-x-y

10x + 5y + 1(38-x-y) = 147

9x + 4y = 109

x and y must be integers.

sketch 9x + 4y = 108

x-intercept is 12

y-intercept is 27

y = (109-9x)/4 , we know 0 < x < 12

after some trial and error, x = 9 (only had to try odd x's)

x = 9

y = 7

9 tens

7 fives and

22 ones

check: 90 + 35 + 22 = 147

- algebra -
**PsyDAG**, Monday, November 12, 2012 at 1:09pmLet x = $5, then x+3 = $1 and .5x = $10. Then:

x + (x+3) + .5x = 38

2.5x = 35

x = 14, x+3 = 17 and .5x = 7

To check:

5*14 + 17 + 10(7) = 147

157 ≠ 147

It doesn't check. Do you have typo?

- oops - algebra -
**Reiny**, Monday, November 12, 2012 at 1:21pmShould have read the question more carefully, looks like I anticipated the question.

tens --- x

fives --- 2x, it said so

ones -- 2x+3

10x + 5(2x) + 1(2x+3) = 147

22x = 144

x = 144/22 , which is not a whole number

There is no solution.

I agree with PsyDAG

- algebra -
**Elise**, Monday, November 12, 2012 at 8:40pmThanks! No typo, it must just be another trick up my teacher's sleeve!

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